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Show that trace of AB = trace of BA

> A:=Matrix([[a,b],[c,d]]);

> B:=Matrix([[p,q],[r,s]]);

A := _rtable[8101584]

B := _rtable[8088992]

> A.B;

_rtable[20399132]

> B.A;

_rtable[18749952]

> trace(A.B);

a*p+b*r+c*q+d*s

> trace(B.A);

a*p+b*r+c*q+d*s

發現兩者trace相等 故得證